finding last digit

How do I find the last digit of a number and output text accordingly? This
is the code I'm trying to use, but isn't working:

function ending() {
$count_digits = preg_split('//', $result->hit_count, -1,
PREG_SPLIT_NO_EMPTY);
$count_len = strlen($result->hit_count);
$count_end_digit = $count_digits[$count_len--];
if ($count_end_digit == 1) {print "st";}
elseif ($count_end_digit == 2) {print "nd";}
elseif ($count_end_digit == 3) {print "rd";}
else {print "th";}
}

I call it later with print "You are the" . $result->hit_count . ending()
.. " visitor";

$result->hit_count is a variable I created for getting the value from a
MySQL database. I can easily output the number, so the variable isn't the
problem. What is?

On 27-Aug-2003, "Marc" <marb291@hotmail.com> wrote:

> How do I find the last digit of a number and output text accordingly? This
> is the code I'm trying to use, but isn't working:
>
> function ending() {
> $count_digits = preg_split('//', $result->hit_count, -1,
> PREG_SPLIT_NO_EMPTY);
> $count_len = strlen($result->hit_count);
> $count_end_digit = $count_digits[$count_len--];
> if ($count_end_digit == 1) {print "st";}
> elseif ($count_end_digit == 2) {print "nd";}
> elseif ($count_end_digit == 3) {print "rd";}
> else {print "th";}
> }
>
> I call it later with print "You are the" . $result->hit_count .
> ending()
> . " visitor";
>
> $result->hit_count is a variable I created for getting the value from a
> MySQL database. I can easily output the number, so the variable isn't the
> problem. What is?

Among other things $result is out of scope in ending()
Try:
function ending($s)
{
if (strlen($s)<1) return '';
$lastchar = substr($s,strlen($s)-1);
if ($lastchar == '1') return 'st';
if ($lastchar == '2') return 'nd';
if ($lastchar == '3') return 'rd';
return 'th';
}
print 'You are the'.$result->hit_count.ending($result->hit_count).'
visitor.'

--
Tom Thackrey
www.creative-light.com

Hey Mark

You're camplicationg everything,

If you'd like to now last digit do following:

$ends = array ( 1 => 'st', 2 => 'nd', 3 => 'rd' );
$count_end_digit = $result->hit_count % 10;
echo "You are the" . $result->hit_count . ( isset($ends[$count_end_digit]) ?
$ends[$count_end_digit] : "th"" );

That's it.

Best,
Dima

> How do I find the last digit of a number and output text accordingly? This
> is the code I'm trying to use, but isn't working:
>
> function ending() {
> $count_digits = preg_split('//', $result->hit_count, -1,
> PREG_SPLIT_NO_EMPTY);
> $count_len = strlen($result->hit_count);
> $count_end_digit = $count_digits[$count_len--];
> if ($count_end_digit == 1) {print "st";}
> elseif ($count_end_digit == 2) {print "nd";}
> elseif ($count_end_digit == 3) {print "rd";}
> else {print "th";}
> }
>
> I call it later with print "You are the" . $result->hit_count .
ending()
> . " visitor";
>
> $result->hit_count is a variable I created for getting the value from a
> MySQL database. I can easily output the number, so the variable isn't the
> problem. What is?
>
>