variable scope issue?

Within a function I have declared a variable and given it a value based on a
database query. (see code below)

if(!$next){
$next=0;
}
$rpp = 20; //results per page
$query = "select * from header where parent = $postid order by posted
desc limit $next, $rpp";
$result = mysql_query($query);


Within a different function I would like to test whether this variable has a
value (see below)

if($result){
$num_msgs = mysql_numrows($result);
$prev = $next - $rpp;
$next += $rpp;
echo"<tr><td colspan='3' bgcolor = '#ffffff' align = 'right'>";
if($next <= $num_msgs)echo"<a href=\"forum.php?next=$next\">Older
Messages</a>";
if(($next <= $num_msgs) && ($prev >=
0))echo"&nbsp;&nbsp;|&nbsp;&nbsp;";
if($prev >= 0)echo"<a href=\"forum.php?next=$prev\">Newer
Messages</a>";
echo"</td></tr>";
}

Problem is the 2nd function doesn't appear to see the original variable and
therefore doesn't execute the code. Is there some way I can pass the
variable and its contents to the2nd function to allow this code to execute?

Appreciate your suggestions
David

"David & Angela Ehmer" <ehmer@pacific.net.au> wrote in message
news:io4%a.1004$d6.73392@nasal.pacific.net.au...
> Within a function I have declared a variable and given it a value based on
a
> database query. (see code below)

you coud declare it as global in both functions. Alternatively (an more
cleanly) you could return it as the result ogf the first function and give
it as parameter for the first. Or even better, if both functions are in the
same class you could use class instance variable (one declared in class and
accessed with $this->varname).

rush
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