Learning PHP - Need Help with Forms (Checkboxes)

Kenneth Pardue say...

> Here's what I have:
>
> In my form:
> <input type='checkbox' name='checkbox[]' value='Option 1'>
> <input type='checkbox' name='checkbox[]' value='Option 2'>
> <input type='checkbox' name='checkbox[]' value='Option 3'>

using checkbox above will not pass the variables to php like you intend,
because as far as HTML is concerned, 'checkbox[]' isn't an array.

So basically checkbox[] will only get passed as one of the above options,
not all 3 (if all 3 are checked)

You need to state the array keys in your html form.

eg

<input type='checkbox' name='checkbox[0]' value='Option 1'>
<input type='checkbox' name='checkbox[1]' value='Option 2'>
<input type='checkbox' name='checkbox[2]' value='Option 3'>

I think this is the problem anyway

HTH

--
Nathan.
XBL Gamertag: Cowfield
http://www.cowfields.com
Bow to the Cow!

Nathan say...

> I think this is the problem anyway

D'oh! It isn't. Ignore the above post. it's late and I need my bed.

leave the form as is, but your processing script should be like this:

$strengths = $_REQUEST['strengths'];

echo "<p>" . $strengths[0] . $strengths[1] . $strengths[2] . "</p>"

Basically, lose the square brackets. Using square brackets is for dealing
with one value of an array, losing the brackets means the array as a whole.
I think anyway

--
Nathan.
XBL Gamertag: Cowfield
http://www.cowfields.com
Bow to the Cow!

Kenneth Pardue wrote:

> Hmmmm, this is odd. Trying it the second way seems to work if I have a
> combination of any two or all three checked (with the caveat that when I
> print them out I have the word "Array" thrown at the end of them).
> Selecting just one or none results in an undefined offset error.
>
> Trying it with a combination of your first post
> (name='strengths[1]'...etc) results in it working, but I get that
> accursed undefined offset error for options that are unchecked.
>
> Kenneth
>
>
> Nathan wrote:
>
>> Nathan say...
>>
>>
>>> I think this is the problem anyway
>>
>>
>>
>> D'oh! It isn't. Ignore the above post. it's late and I need my bed.
>>
>> leave the form as is, but your processing script should be like this:
>>
>> $strengths = $_REQUEST['strengths'];
>>
>> echo "<p>" . $strengths[0] . $strengths[1] . $strengths[2] . "</p>"
>>
>> Basically, lose the square brackets. Using square brackets is for
>> dealing with one value of an array, losing the brackets means the
>> array as a whole. I think anyway
>>

You can do

echo "<p> @$strengths[0] $@strengths[1] @$strengths[2] </p>";

hope tha helps



--
From the mind of Andrew Kicks
Remove nospam to reply

Kicksy wrote:

> Kenneth Pardue wrote:
>
>> Hmmmm, this is odd. Trying it the second way seems to work if I have
>> a combination of any two or all three checked (with the caveat that
>> when I print them out I have the word "Array" thrown at the end of
>> them). Selecting just one or none results in an undefined offset error.
>>
>> Trying it with a combination of your first post
>> (name='strengths[1]'...etc) results in it working, but I get that
>> accursed undefined offset error for options that are unchecked.
>>
>> Kenneth
>>
>>
>> Nathan wrote:
>>
>>> Nathan say...
>>>
>>>
>>>> I think this is the problem anyway
>>>
>>>
>>>
>>>
>>> D'oh! It isn't. Ignore the above post. it's late and I need my bed.
>>>
>>> leave the form as is, but your processing script should be like this:
>>>
>>> $strengths = $_REQUEST['strengths'];
>>>
>>> echo "<p>" . $strengths[0] . $strengths[1] . $strengths[2] . "</p>"
>>>
>>> Basically, lose the square brackets. Using square brackets is for
>>> dealing with one value of an array, losing the brackets means the
>>> array as a whole. I think anyway
>>>
>
> You can do
>
> echo "<p> @$strengths[0] $@strengths[1] @$strengths[2] </p>";
> ||||

Should be @$strengths[1]

sorry. I blame the keyboard.
> hope tha helps
>
>
>


--
From the mind of Andrew Kicks
Remove nospam to reply