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Old 07-02-2007, 10:58 AM   #1
Eugenio Zinga
 
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In the first place excused my English.
I do not succeed to understand as the result of the query with 2 tables
never is of the values mistakes to you while with 1 table the result is
right.
Thanks Eugene

table ART:
------
IDart
01
02
03

table MOV1:
-------
IDart qta
01 100
02 100
03 100
01 100
03 50

query1:
SELECT IDart, SUM(MOV1.qta) as TMOV1
FROM ART
LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
GROUP BY ART.IDart

result query OK:
IDart TMOV1
01 200
02 100
03 150

==================================

table MOV2:
-------
IDart qta
01 10
02 30
03 20
01 10
03 5

query2:
SELECT IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
FROM ART
LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
GROUP BY ART.IDart

result query NO OK:
IDart TMOV1 TMOV2
01 8210 ? 10000 ?
02 3200 ? 9300 ?
03 1720 ? 4000 ?
 
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Old 07-02-2007, 10:58 AM   #2
strawberry
 
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On Jun 22, 8:52 am, "Eugenio Zinga" <eugzi...@tin.it> wrote:
> In the first place excused my English.
> I do not succeed to understand as the result of the query with 2 tables
> never is of the values mistakes to you while with 1 table the result is
> right.
> Thanks Eugene
>
> table ART:
> ------
> IDart
> 01
> 02
> 03
>
> table MOV1:
> -------
> IDart qta
> 01 100
> 02 100
> 03 100
> 01 100
> 03 50
>
> query1:
> SELECT IDart, SUM(MOV1.qta) as TMOV1
> FROM ART
> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
> GROUP BY ART.IDart
>
> result query OK:
> IDart TMOV1
> 01 200
> 02 100
> 03 150
>
> ==================================
>
> table MOV2:
> -------
> IDart qta
> 01 10
> 02 30
> 03 20
> 01 10
> 03 5
>
> query2:
> SELECT IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
> FROM ART
> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
> LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
> GROUP BY ART.IDart
>
> result query NO OK:
> IDart TMOV1 TMOV2
> 01 8210 ? 10000 ?
> 02 3200 ? 9300 ?
> 03 1720 ? 4000 ?

Query:

SELECT ART.IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
FROM ART
LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
GROUP BY ART.IDart

Result:

IDart TMOV1 TMOV2
1 400 40
2 100 30
3 300 50
 
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Old 07-02-2007, 10:58 AM   #3
Eugenio Zinga
 
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"strawberry" <zac.carey@gmail.com> ha scritto nel messaggio
news:1182505502.442836.295500@c77g2000hse.googlegr oups.com...
> On Jun 22, 8:52 am, "Eugenio Zinga" <eugzi...@tin.it> wrote:
>> In the first place excused my English.
>> I do not succeed to understand as the result of the query with 2 tables
>> never is of the values mistakes to you while with 1 table the result is
>> right.
>> Thanks Eugene
>>
>> table ART:
>> ------
>> IDart
>> 01
>> 02
>> 03
>>
>> table MOV1:
>> -------
>> IDart qta
>> 01 100
>> 02 100
>> 03 100
>> 01 100
>> 03 50
>>
>> query1:
>> SELECT IDart, SUM(MOV1.qta) as TMOV1
>> FROM ART
>> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
>> GROUP BY ART.IDart
>>
>> result query OK:
>> IDart TMOV1
>> 01 200
>> 02 100
>> 03 150
>>
>> ==================================
>>
>> table MOV2:
>> -------
>> IDart qta
>> 01 10
>> 02 30
>> 03 20
>> 01 10
>> 03 5
>>
>> query2:
>> SELECT IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
>> FROM ART
>> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
>> LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
>> GROUP BY ART.IDart
>>
>> result query NO OK:
>> IDart TMOV1 TMOV2
>> 01 8210 ? 10000 ?
>> 02 3200 ? 9300 ?
>> 03 1720 ? 4000 ?
>
> Query:
>
> SELECT ART.IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
> FROM ART
> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
> LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
> GROUP BY ART.IDart
>
> Result:
>
> IDart TMOV1 TMOV2
> 1 400?? 40 ??
> 2 100 30
> 3 300 50
>
Thanks for your answer. How you see the total of code 1 is mistaken like
never?
IDart TMOV1 TMOV2
> 1 200 20 Ok
> 2 100 30
> 3 300 50
 
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Old 07-02-2007, 10:59 AM   #4
Eugenio Zinga
 
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strawberry help!!



"Eugenio Zinga" <eugzinga@tin.it> ha scritto nel messaggio
news:467ba496$0$4791$4fafbaef@reader4.news.tin.it. ..
>
> "strawberry" <zac.carey@gmail.com> ha scritto nel messaggio
> news:1182505502.442836.295500@c77g2000hse.googlegr oups.com...
>> On Jun 22, 8:52 am, "Eugenio Zinga" <eugzi...@tin.it> wrote:
>>> In the first place excused my English.
>>> I do not succeed to understand as the result of the query with 2 tables
>>> never is of the values mistakes to you while with 1 table the result is
>>> right.
>>> Thanks Eugene
>>>
>>> table ART:
>>> ------
>>> IDart
>>> 01
>>> 02
>>> 03
>>>
>>> table MOV1:
>>> -------
>>> IDart qta
>>> 01 100
>>> 02 100
>>> 03 100
>>> 01 100
>>> 03 50
>>>
>>> query1:
>>> SELECT IDart, SUM(MOV1.qta) as TMOV1
>>> FROM ART
>>> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
>>> GROUP BY ART.IDart
>>>
>>> result query OK:
>>> IDart TMOV1
>>> 01 200
>>> 02 100
>>> 03 150
>>>
>>> ==================================
>>>
>>> table MOV2:
>>> -------
>>> IDart qta
>>> 01 10
>>> 02 30
>>> 03 20
>>> 01 10
>>> 03 5
>>>
>>> query2:
>>> SELECT IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
>>> FROM ART
>>> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
>>> LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
>>> GROUP BY ART.IDart
>>>
>>> result query NO OK:
>>> IDart TMOV1 TMOV2
>>> 01 8210 ? 10000 ?
>>> 02 3200 ? 9300 ?
>>> 03 1720 ? 4000 ?
>>
>> Query:
>>
>> SELECT ART.IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
>> FROM ART
>> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
>> LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
>> GROUP BY ART.IDart
>>
>> Result:
>>
>> IDart TMOV1 TMOV2
>> 1 400?? 40 ??
>> 2 100 30
>> 3 300 50
>>
> Thanks for your answer. How you see the total of code 1 is mistaken like
> never?
> IDart TMOV1 TMOV2
>> 1 200 20 Ok
>> 2 100 30
>> 3 300 50
>
>
 
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Old 07-02-2007, 10:59 AM   #5
strawberry
 
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On Jun 25, 7:00 am, "Eugenio Zinga" <eugzi...@tin.it> wrote:
> strawberry help!!
>
> "Eugenio Zinga" <eugzi...@tin.it> ha scritto nel messaggionews:467ba496$0$4791$4fafbaef@reader4.new s.tin.it...
>
>
>
> > "strawberry" <zac.ca...@gmail.com> ha scritto nel messaggio
> >news:1182505502.442836.295500@c77g2000hse.googleg roups.com...
> >> On Jun 22, 8:52 am, "Eugenio Zinga" <eugzi...@tin.it> wrote:
> >>> In the first place excused my English.
> >>> I do not succeed to understand as the result of the query with 2 tables
> >>> never is of the values mistakes to you while with 1 table the result is
> >>> right.
> >>> Thanks Eugene
>
> >>> table ART:
> >>> ------
> >>> IDart
> >>> 01
> >>> 02
> >>> 03
>
> >>> table MOV1:
> >>> -------
> >>> IDart qta
> >>> 01 100
> >>> 02 100
> >>> 03 100
> >>> 01 100
> >>> 03 50
>
> >>> query1:
> >>> SELECT IDart, SUM(MOV1.qta) as TMOV1
> >>> FROM ART
> >>> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
> >>> GROUP BY ART.IDart
>
> >>> result query OK:
> >>> IDart TMOV1
> >>> 01 200
> >>> 02 100
> >>> 03 150
>
> >>> ==================================
>
> >>> table MOV2:
> >>> -------
> >>> IDart qta
> >>> 01 10
> >>> 02 30
> >>> 03 20
> >>> 01 10
> >>> 03 5
>
> >>> query2:
> >>> SELECT IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
> >>> FROM ART
> >>> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
> >>> LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
> >>> GROUP BY ART.IDart
>
> >>> result query NO OK:
> >>> IDart TMOV1 TMOV2
> >>> 01 8210 ? 10000 ?
> >>> 02 3200 ? 9300 ?
> >>> 03 1720 ? 4000 ?
>
> >> Query:
>
> >> SELECT ART.IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
> >> FROM ART
> >> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
> >> LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
> >> GROUP BY ART.IDart
>
> >> Result:
>
> >> IDart TMOV1 TMOV2
> >> 1 400?? 40 ??
> >> 2 100 30
> >> 3 300 50
>
> > Thanks for your answer. How you see the total of code 1 is mistaken like
> > never?
> > IDart TMOV1 TMOV2
> >> 1 200 20 Ok
> >> 2 100 30
> >> 3 300 50

Well here's one way:

SELECT a.art_id,x.TMOV1,y.TMOV2 FROM art a
LEFT JOIN
(SELECT art.art_id, SUM(MOV1.qta) as TMOV1
FROM ART
LEFT JOIN MOV1 ON ART.art_id = MOV1.art_id
GROUP BY ART.art_id)x
ON a.art_id = x.art_id
LEFT JOIN
(SELECT art.art_id, SUM(MOV2.qta) as TMOV2
FROM ART
LEFT JOIN MOV2 ON ART.art_id = MOV2.art_id
GROUP BY ART.art_id)y
ON a.art_id = y.art_id
 
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Old 07-02-2007, 10:59 AM   #6
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On Jun 25, 10:46 am, strawberry <zac.ca...@gmail.com> wrote:
> On Jun 25, 7:00 am, "Eugenio Zinga" <eugzi...@tin.it> wrote:
>
>
>
> > strawberry help!!
>
> > "Eugenio Zinga" <eugzi...@tin.it> ha scritto nel messaggionews:467ba496$0$4791$4fafbaef@reader4.new s.tin.it...
>
> > > "strawberry" <zac.ca...@gmail.com> ha scritto nel messaggio
> > >news:1182505502.442836.295500@c77g2000hse.googleg roups.com...
> > >> On Jun 22, 8:52 am, "Eugenio Zinga" <eugzi...@tin.it> wrote:
> > >>> In the first place excused my English.
> > >>> I do not succeed to understand as the result of the query with 2 tables
> > >>> never is of the values mistakes to you while with 1 table the result is
> > >>> right.
> > >>> Thanks Eugene
>
> > >>> table ART:
> > >>> ------
> > >>> IDart
> > >>> 01
> > >>> 02
> > >>> 03
>
> > >>> table MOV1:
> > >>> -------
> > >>> IDart qta
> > >>> 01 100
> > >>> 02 100
> > >>> 03 100
> > >>> 01 100
> > >>> 03 50
>
> > >>> query1:
> > >>> SELECT IDart, SUM(MOV1.qta) as TMOV1
> > >>> FROM ART
> > >>> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
> > >>> GROUP BY ART.IDart
>
> > >>> result query OK:
> > >>> IDart TMOV1
> > >>> 01 200
> > >>> 02 100
> > >>> 03 150
>
> > >>> ==================================
>
> > >>> table MOV2:
> > >>> -------
> > >>> IDart qta
> > >>> 01 10
> > >>> 02 30
> > >>> 03 20
> > >>> 01 10
> > >>> 03 5
>
> > >>> query2:
> > >>> SELECT IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
> > >>> FROM ART
> > >>> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
> > >>> LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
> > >>> GROUP BY ART.IDart
>
> > >>> result query NO OK:
> > >>> IDart TMOV1 TMOV2
> > >>> 01 8210 ? 10000 ?
> > >>> 02 3200 ? 9300 ?
> > >>> 03 1720 ? 4000 ?
>
> > >> Query:
>
> > >> SELECT ART.IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
> > >> FROM ART
> > >> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
> > >> LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
> > >> GROUP BY ART.IDart
>
> > >> Result:
>
> > >> IDart TMOV1 TMOV2
> > >> 1 400?? 40 ??
> > >> 2 100 30
> > >> 3 300 50
>
> > > Thanks for your answer. How you see the total of code 1 is mistaken like
> > > never?
> > > IDart TMOV1 TMOV2
> > >> 1 200 20 Ok
> > >> 2 100 30
> > >> 3 300 50
>
> Well here's one way:
>
> SELECT a.art_id,x.TMOV1,y.TMOV2 FROM art a
> LEFT JOIN
> (SELECT art.art_id, SUM(MOV1.qta) as TMOV1
> FROM ART
> LEFT JOIN MOV1 ON ART.art_id = MOV1.art_id
> GROUP BY ART.art_id)x
> ON a.art_id = x.art_id
> LEFT JOIN
> (SELECT art.art_id, SUM(MOV2.qta) as TMOV2
> FROM ART
> LEFT JOIN MOV2 ON ART.art_id = MOV2.art_id
> GROUP BY ART.art_id)y
> ON a.art_id = y.art_id

I guess the real problem is the lack of a PRIMARY KEY on your MOV
tables.
 
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Old 07-02-2007, 10:59 AM   #7
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Not there is primary key in tables MOV.
Infinite thanks.
--------------
"strawberry" <zac.carey@gmail.com> ha scritto nel messaggio
news:1182766326.722684.304870@p77g2000hsh.googlegr oups.com...
> On Jun 25, 10:46 am, strawberry <zac.ca...@gmail.com> wrote:
>> On Jun 25, 7:00 am, "Eugenio Zinga" <eugzi...@tin.it> wrote:
>>
>>
>>
>> > strawberry help!!
>>
>> > "Eugenio Zinga" <eugzi...@tin.it> ha scritto nel
>> > messaggionews:467ba496$0$4791$4fafbaef@reader4.new s.tin.it...
>>
>> > > "strawberry" <zac.ca...@gmail.com> ha scritto nel messaggio
>> > >news:1182505502.442836.295500@c77g2000hse.googleg roups.com...
>> > >> On Jun 22, 8:52 am, "Eugenio Zinga" <eugzi...@tin.it> wrote:
>> > >>> In the first place excused my English.
>> > >>> I do not succeed to understand as the result of the query with 2
>> > >>> tables
>> > >>> never is of the values mistakes to you while with 1 table the
>> > >>> result is
>> > >>> right.
>> > >>> Thanks Eugene
>>
>> > >>> table ART:
>> > >>> ------
>> > >>> IDart
>> > >>> 01
>> > >>> 02
>> > >>> 03
>>
>> > >>> table MOV1:
>> > >>> -------
>> > >>> IDart qta
>> > >>> 01 100
>> > >>> 02 100
>> > >>> 03 100
>> > >>> 01 100
>> > >>> 03 50
>>
>> > >>> query1:
>> > >>> SELECT IDart, SUM(MOV1.qta) as TMOV1
>> > >>> FROM ART
>> > >>> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
>> > >>> GROUP BY ART.IDart
>>
>> > >>> result query OK:
>> > >>> IDart TMOV1
>> > >>> 01 200
>> > >>> 02 100
>> > >>> 03 150
>>
>> > >>> ==================================
>>
>> > >>> table MOV2:
>> > >>> -------
>> > >>> IDart qta
>> > >>> 01 10
>> > >>> 02 30
>> > >>> 03 20
>> > >>> 01 10
>> > >>> 03 5
>>
>> > >>> query2:
>> > >>> SELECT IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
>> > >>> FROM ART
>> > >>> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
>> > >>> LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
>> > >>> GROUP BY ART.IDart
>>
>> > >>> result query NO OK:
>> > >>> IDart TMOV1 TMOV2
>> > >>> 01 8210 ? 10000 ?
>> > >>> 02 3200 ? 9300 ?
>> > >>> 03 1720 ? 4000 ?
>>
>> > >> Query:
>>
>> > >> SELECT ART.IDart, SUM(MOV1.qta) as TMOV1, SUM(MOV2.qta) as TMOV2
>> > >> FROM ART
>> > >> LEFT JOIN MOV1 ON ART.IDart = MOV1.IDart
>> > >> LEFT JOIN MOV2 ON ART.IDart = MOV2.IDart
>> > >> GROUP BY ART.IDart
>>
>> > >> Result:
>>
>> > >> IDart TMOV1 TMOV2
>> > >> 1 400?? 40 ??
>> > >> 2 100 30
>> > >> 3 300 50
>>
>> > > Thanks for your answer. How you see the total of code 1 is mistaken
>> > > like
>> > > never?
>> > > IDart TMOV1 TMOV2
>> > >> 1 200 20 Ok
>> > >> 2 100 30
>> > >> 3 300 50
>>
>> Well here's one way:
>>
>> SELECT a.art_id,x.TMOV1,y.TMOV2 FROM art a
>> LEFT JOIN
>> (SELECT art.art_id, SUM(MOV1.qta) as TMOV1
>> FROM ART
>> LEFT JOIN MOV1 ON ART.art_id = MOV1.art_id
>> GROUP BY ART.art_id)x
>> ON a.art_id = x.art_id
>> LEFT JOIN
>> (SELECT art.art_id, SUM(MOV2.qta) as TMOV2
>> FROM ART
>> LEFT JOIN MOV2 ON ART.art_id = MOV2.art_id
>> GROUP BY ART.art_id)y
>> ON a.art_id = y.art_id
>
> I guess the real problem is the lack of a PRIMARY KEY on your MOV
> tables.
>
 
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