Am I doing this right???

On Mon, 30 Jun 2003 23:54:07 GMT, "Josh Dawg"
<slopeking7@nospam-earthlink.net> wrote:

>I took a C++ turtorial and it said that the coding for displaying text is:
>
>cout<<"what ever you want to write";
>
>but it won't work for me, is there something wrong in the coding or is my
>compiler messed up?

I can't believe no one hit this obvious problem:

cout is within the namespace std - your problem is that you should
have written:

#include <iostream>

int main()
{
std::cout << "whatever you want to write" << std::endl;
//the std::endl may not be necessary (it skips a line and forces cout
//to display (iirc))

//you can avoid writing std:: before every command if you type
//using namespace std; right after the #include statement but
//that's bad programming practice - a better way might be to
//type using std::cout; and using std::endl; - now your only line of
//code can be:
// cout << "whatever you want to write" << endl;

return 0;
}


Alex
atheist #2007

whoever thought that stream style's format was an improvement over good ole
printf()
must of been either smoking something or trying to justify their job.

Alex wrote:

> On Mon, 30 Jun 2003 23:54:07 GMT, "Josh Dawg"
> <slopeking7@nospam-earthlink.net> wrote:
>
> >I took a C++ turtorial and it said that the coding for displaying text is:
> >
> >cout<<"what ever you want to write";
> >
> >but it won't work for me, is there something wrong in the coding or is my
> >compiler messed up?
>
> I can't believe no one hit this obvious problem:
>
> cout is within the namespace std - your problem is that you should
> have written:
>
> #include <iostream>
>
> int main()
> {
> std::cout << "whatever you want to write" << std::endl;
> //the std::endl may not be necessary (it skips a line and forces cout
> //to display (iirc))
>
> //you can avoid writing std:: before every command if you type
> //using namespace std; right after the #include statement but
> //that's bad programming practice - a better way might be to
> //type using std::cout; and using std::endl; - now your only line of
> //code can be:
> // cout << "whatever you want to write" << endl;
>
> return 0;
> }
>
> Alex
> atheist #2007

On Wed, 02 Jul 2003 07:34:41 GMT, Eternal Vigilance <wotan@oneeye.com>
wrote:

>whoever thought that stream style's format was an improvement over good ole
>printf()
>must of been either smoking something or trying to justify their job.

Are you able to overload printf() so that you can do the following
(real question since I never used "good ole printf()" since it was
before my time)?

myClass myObject;
//assign values to myObject's members here

cout << myObject;

============== SCREEN RESULTS
my1stVar = 32
my2ndVar = The rain in Spain is wet.
my4thVar = -2



Alex
atheist #2007

look up the function its in <stdio.h>

int printf( const char *format [, argument]... );

^^^^^ format string can be a Var itself so you can change
the format in program......

printf("text %d <- int %s<- string %x<- int as hex <cr><lf> ---> \n",
var1,string,var2);


fprintf similar but to a file......
sprintf similar but outputs to a char array (string)


I use them mostly for building error strings for output or logfile entries
(shorter and more readable codewise)
(like another poster said it is a bit slower than explicit string building
itoa() strcat() etc.... )

you could use printf in your overloaded << operator to output what you want
for object data dump



sprintf(&outstr[0]," Object[%d] X=%f Y=%f Z=%f HP=%d /n",
objx->index, objx->xPos, objx->yPos, objx->zPos, objx->HP);

outstr[] contains:
Object[23] X=4.3434 Y=56.5555 Z=1.0000 HP=100


Alex wrote:

> On Wed, 02 Jul 2003 20:34:59 GMT, "Tony Di Croce"
> <iaretony@hotmail.com> wrote:
>
> >No, but to be fair, you had to OVERLOAD the operator... The implementation
> >is somewhere...
>
> Yes, that's the core of my question: can you overload printf()?
>
> Alex
> atheist #2007

www.dcs.shef.ac.uk/~u0ke
"Alex" <support@microsoft.com> wrote in message
news:7n68gvo0r88itqlk8k5j2isc61682hdj94@4ax.com...
> On Thu, 03 Jul 2003 10:46:56 GMT, Eternal Vigilance <wotan@oneeye.com>
> wrote:
>
> >you could use printf in your overloaded << operator to output what you
want
> >for object data dump
>
> But could you do printf(myObject); and print out the member variables
> in a nice little format?
>
>
> Alex
> atheist #20

Are you trying to do something like in java wher eyou can overload an
objects 'toString()' method? i.e myObject.printf()?

--
Kemal Enver
u0ke@dcs.shef.ac.uk

On Thu, 3 Jul 2003 22:10:13 +0100, "Kemal Enver" <kemalenver@f2s.com>
wrote:

>Are you trying to do something like in java wher eyou can overload an
>objects 'toString()' method? i.e myObject.printf()?

I'm asking if it's possible. Not sure about the Java.

In the end I don't really need to know, I'm just exploring the
advantages of cpp's cout << as opposed to the printf() function. I'm
not even sure if this is the best advantage - it probably isn't -
since I know close to nothing about C.


Alex
atheist #2007